Quote:
What this means is that your tube-based system experiences a force, and thus gains momentum, from that initial acceleration of the air from rest to the speed of sound - a force determined by [Pt-Pe]Ae. However, the force generated by mass flow - and thus that momentum - is countered by an equal but opposite "choking" force. Ergo m(dot)Ve is zero with a tube.


still the mass will come out of the tank given its tube is
58 inch diameter.

and when the mass comes out , and it will come out , the momentum will be mass x velocity.

P=m*V

I dont care how you word it , the pipe will move.

because the mass moves inside.

lets check this...

the pressure differential is

114.7 psi - 14.7 psi = 100 psi

the force is 100 lb/sq inch.

the cross sectional area of the 58 inch tube is
2642.079 sq inch
the air inside the tank weights 0.645 lbs / cu ft
2642.079 cu ft / 1728 cu in = 1.528 cu ft in the cross section

suppose the cross section is 1 inch long.

there is 1.528 cu ft in the cross section.

1.528 cu ft * 0.645 lbs = 0.955 lbs in the cross section

there are 2642.079 sq inches in the cross section

.955 / 2642.079 = 0.0003614577 lb per cu inch of area.

a=f/m

a = 100 psi / 0.0003614577 lbs = 276,657.545 fps

276,657.545 fps / 5280 ft = 52.3972 miles per second.

276 657.545 fps = 84,325.219 meters / second


this incorporates the resistive force and friction is pretty much null in a tube this large especially with air as the fluid.

there is no choking force involved in this situation
there is only fluid flow.

and that restriction is minimal if not non existant
in a pipe this large.

the larger area did not reduce the velocity below the
340.29 m/s^2
the same mass is involved.

so the momentum I stated earlier is the same
the momentum is 99,557 kg-m/s








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3/4 inch of dust build up on the moon in 4.527 billion years,LOL and QM is fantasy science.