Originally Posted By: paul

applying less force will not stop it as fast and will also require more stopping distance.

applying more force will stop it faster and in less stopping distance.

Yea. So if we need <<2s turnaround time we have to use a higher force. 5219N takes 2s and 104m to turn the mass around.


a=-100,000N / 100kg

time = (change in v) /a
time to stop = -52.2m/s / (-1000m/s^2)
time to stop = 0.0522s

distance to stop = -1/2 a t^2
distance to stop = 1.36m

Equations from equations of motion