are you talking trash again , kallog like the below trash you posted.

- The pipe starts with momentum
pp = 0
- An accelerated mass starts with momentum p1.
- After acceleration at force F for time t it ends up with momentum p1+F*t. The reaction has the opposite effect on the pipe,
pp = 0-F*t
- After turning around 180deg, its momentum in the free-floating stage is -(p1+F*t). This is a change in momentum of -2*(p1+F*t), so the reaction on pipe causes the opposite change in momentum. The pipe gains 2*(p1+F*t),
pp = 0-F*t+2(p1+F*t)
- But at the same time a free-floater is turning around at the other end, imparting momentum -2*p1 onto the pipe.
pp = 0-F*t+2(p1+F*t)-2*p1
Then that just-turned-around free-floater starts to accelerate, imparting -F*t to the pipe during it's travels.
pp = 0-F*t+2(p1+F*t)-2*p1-F*t

originally I thought you were only talking about the two
masses that are being turned around at the ends but from your
last post it seems that this must be where you atttempted
to show that the "pipe" would not move.

what a farce of physics...

explaining away 22 masses using only 2 masses.
but normal for your type of genius.

why didnt you add some numbers in the above genius?

you know like 100 kg accelerated at 5 m/s

for a distance of 500 ft then repeat the above

for the other 19 masses being accelerated.

these 20 forces add up to the forces applied to the pipe for movement.

then add up what little negative forces there are from the 2 masses being turned around.

in your poisoned mind you neglect that there are

TWENTY , 20 , MASSES being accelerated at any moment.


but I suppose that is the only way you can show no pipe movement.


the results are no matter how scrambled your brains are...

at any moment.

there are 20 forces being applied to the pipe that cause
the pipe to move.

and the pipe is not as stupid as you guys are so it dont know it needs to stop just to serve you two guys misinterpretation of newtons laws suddenly as soon as it has traveled the lenght of the pipe. LOL , sickening.

at any moment there are 20 forces that are moving the pipe
and the two forces at the ends would in no way cancel out the 20 forces that move the pipe.

suppose each mass being accelerated applies a force
of 25 kg to the pipe.

that means that each mass can only subtract 25 kg from the pipe.

there are 20 masses at any time supplying a force of 20 kg
so 20 * 25kg = 500kg

now when 1 reaches the end the most it can subtract is

25 kg.

result = 475 kg ---> pipe
25 kg <--- turnaround

so when 2 reach the end
result = 450 kg ---> pipe
50 kg <--- turnaround

see what wonders numbers can do.

and I didnt even use close numbers.

just simple grade school numbers that you two might understand.

when one of the masses moves through the 180 turnaround
do you think it alone will subtract more force than the 20 being accelerated towards the end?

just how dumb are you guys?

no way , the most that the one single mass could possibly subtract is the amount of force that would be required to stop it completely.

no tweedle dumb and tweedle dumber physics dont work that way.

so maybe you can tell us exactly how the two masses turning around will apply more force than the 20 masses being accelerated and keep the pipe from moving.

your wrong and Im right.

kallogs bloopers

- After turning around 180deg, its momentum in the free-floating stage is -(p1+F*t).

so according to your brain the mass that has been accelerating for the lenght of the pipe will suddenly
lose all momentum that it has gained...?

that way you have an exact number that just happens to
have be identical number only its a negatve number.
this way you can say +5 added to -5 = 0 movement.

how convenient and ridiculous to say the least.

this way you can say +5 added to -5 = 0 movement.
or as you put it
pp = 0-F*t+2(p1+F*t)-2*p1-F*t

I never said the ends were brakes their just turnarounds.

3/4 inch of dust build up on the moon in 4.527 billion years,LOL and QM is fantasy science.