All speeds measured relative to the pipe.
1. Railgun accelerates a 20kg mass up to 1m/s
2-10. Same again for other masses
11. Other railgun decelerates the first mass to 0.
12-20. Same again for other masses
21. Same railgun accelerates the first mass to -1m/s.
22-30. Same again for other masses

???

Railguns have reaction forces pushing the pipe the opposite way. I didn't see that mentioned in your post.

well duhhh , thats the reason the pipe moves.

your little 1-30 above is not very well though out.

Quote:
1. Railgun accelerates a 20kg mass up to 1m/s


thats 100 kg and 5 m/s
Im ammased you missed that.
ie....
if each weight weighs 100 kg
and each weight has a velocity of .5 m/s
to find the force needed to achieve the .5 m/s velocity.

F = m*v
F = 100 kg / .5 m/s = 50 kgf
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Quote:
2-10. Same again for other masses

I suppose your are talking about the weights in the turnarounds.

and if for some stupid reason you are sudgesting that one weight is decelerated
while another is accelerated , you are wrong.
Quote:
11. Other railgun decelerates the first mass to 0.

nope , the other rail gun is only used to stop and hold the weights in place.
and to slightly accelerate the weights.

Im not sure that you read the post , because from your assesment it does not appear that way.
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Quote:
11. Other railgun decelerates the first mass to 0.

wrong again , you should take a word comprehension refresher course.
I said that the other rail gun is used to stop or hold the weights.
not to decelerate the weights at the same time as the other weights are accelerating.
its pretty easy to see what I wrote.

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Quote:
12-20. Same again for other masses

nope the opposing weights are floating.

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Quote:
21. Same railgun accelerates the first mass to -1m/s.

wrong again.

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its pretty clear to me that neither of you have much mechanical sence
about you.

Quote:
a = 500 kgf / 500 kg

Ouch. This horrible bastardization of units is why it's easy for me to stop bothering to follow. Sure you're probably correct but there's certainly simpler ways to do it. What on earth does a kgf have to do with a machine floating in space? There's no Earth gravity, no weight of a kg up there. Please use consistent units. Even imperial ones, as long as they satisfy equations like F=ma and v=d/t. Your above equation subtly has acceleration in units of g.


that is terrible isnt it , its exactly how it works in zero g.

notice I did not include resistance.

a mass in space is the same as a mass on earth , only you can push it
with less force because there is zero resistance to movement in zero g.

the only difference betweem a mass on earth and a mass in zero g is
gravity.

it still has the same mass.
so it requires the same force.

do you think you can push a 100 kg mass on earth with a 1 kg force.

no because you have to first overcome the inertia of the mass to get it to
start moving.

because of the resistance.

no such bastardization in zero g , sorry mr know it all.

your wrong again.











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3/4 inch of dust build up on the moon in 4.527 billion years,LOL and QM is fantasy science.