that all depends on your frame of reference and a tree is elastic to a point , then theres the wind resistance as the tree is approached by the car and the wind compresses and pushes back on the car with a momentum of -1000

however since the car is also pushing the compressed air
with a momentuum of +1000 the two momentums cancel each other out , the tree due to the elastisity absorbes the force of the "wind + car" system and the car pushes the tree towards the car at twice the cars momentum.

so after the tree impacts the car the car has a momentum
of car-1000 + tree+2000 = car - 1000.

the car has a momentum of -50,000

then the car will travel at the speed of light in the
opposite direction of its momentum - the doubled tree momentum that is squared and double squared just as the impact occurs due to the right angle acceleration of the wind and its angular velocity.

1000^2^2 w.T1-A1= 50,000

but only if the tree is elastic.
if the tree is not elastic then the results would be different.

which results in

-50,000 + +50,000 = -+50,000

depending on your frame of reference.

tree momentum durring collision is

T1(T/A^2) VC1-w = total tree momentum = +2000^3-%@.()

567,hd *(-) + a^3 / AT = wind angular velocity

so 50,000 - 567,hd = -1000

so although it appears that the tree is colliding with the tree , the compressed air between the "tree+car" system
is absorbing the cars momentum , the tree only looks as if the car is hitting the tree because the car is being pushed backwards by the elasticity of the "air+tree" system at the speed of light-c + 1000.

3/4 inch of dust build up on the moon in 4.527 billion years,LOL and QM is fantasy science.