Quote:
That -80N is the force applied by the accelerator to cause the -0.8m/s^2 acceleration.


well then , OK.
so there is no force that the mass can apply to the turn as the mass enters the turn.

because the mass is no longer accelerating as it enters the turn.

it just slips into a hole.
it doesnt really have any weight because there is very little
gravity in space.

but there would be some friction as the mass presses against the turn going through the turn.

we already know that momentum is not a force and a force is required to push an object.

the mass does have momentum , but momentum is not force.

I have covered the centripetal force.
which is not a outward force.


and the centripetal acceleration.
which is not a outward acceleration.



Quote:
the mass that is passing through the turn is undergoing centripetal acceleration , this acceleration is toward the center of the turn , not away from the center of the turn.


centripetal acceleration is constant acceleration btw.
because the mass is constantly accelerating towards the center.

the centripetal force (center seeking ) = fc = 12568N

so where does this leave us?

heres a good calculator
http://www.calculatoredge.com/new/centripetal.htm#velocity

Quote:
Its velocity changes as it travels through the turn. Its speed does not. The change in velocity means it must transfer momentum with the pipe.


all of the below is in the same context.
--------------------------------------------
since the 100 kg mass does not loose any of its velocity as it travels through the turn then it hasnt given any of its momentum to the pipe.

because it still has its mass and it has 40 m/s velocity
only in a new direction.
--------------------------------------------

Quote:
transfer momentum with the pipe


how is that accomplished?






3/4 inch of dust build up on the moon in 4.527 billion years,LOL and QM is fantasy science.