what does the sentence below mean to you?
The pipe has momentum -1
knowing that a momentum of -1 would be saying that the pipe is moving in the negative direction with a magnatude of 1
Yes.
remember this
Whatever momentum the mass transfers to the pipe, the pipe has to receive from the mass. If the mass gains 2, the pipe has to lose 2.
"momentum becomes more positive".
how does momentum become more positive?
does a gain in momentum require a external force?
you say the pipe that has a magnatude of momentum of 1
and a direction of + will both decelerate to zero momentum
and then accelerate in the opposite direction with a magnatude of momentum of 1 and a direction of -
the mass only has a momentum magnatude of -1
the mass would need a momentum maganatude of -2
to both decelerate the pipe to zero momentum and
then accelerate the pipe to -1.
where did you get the extra force to accelerate the pipe in the opposite direction once the pipe stopped.
or are you saying that the pipe does not need to stop , it just magically switches directions without first stopping?
so how can a vector cause the pipe to stop , start , reverse directions , etc , if there is no force involved?
are you saying that a vector is a force?
In classical mechanics, momentum SI unit
kg·m/s, or, equivalently, N·s
is the product of the mass and velocity of an object (). Like velocity, momentum is a vector quantity, possessing a direction as well as a magnitude.
There's no such thing as "momentum force". This kind of detail is why we're having so much trouble communicating.
there is such a thing as momentum force , thats why momentum is given the symbol p in physics.
if momentum was not a force then you would not use p in equations as in below.
Momentum was not merely the motion, which was motus, but was the
power residing in a moving object
In physics, power is the rate at which
work is performed or energy is converted.
In physics, work is the amount of energy transferred by a
force acting through a distance in the direction of the force.
the result of 2 objects that are not accelerating that collide would be quantified by using p ( the force of momentum ) , otherwise just what would you propose to use
in an equation to calculate the force of the 2 objects colliding.
let me go back and find where you have used p ( momentum )
in this thread.
yes just a few post back you used momentum as if it was a force , exactly the way it is supposed to be used as the momentum of an object is the mass x its velocity.
its velocity includes its direction.
What is the meaning of a negative momentum?
If object A has momentum pA and object B has momentum pB, what is the total momentum of the system comprising A and B?
a) pA + pB
b) pA - pB
b) |pA| + |pB|
c) 0
d) Requires more information to answer
so in the above that you posted earlier you used p for momentum.
what specificaly were you meaning above by
pA + pB ?
its obvious that an A and an B cannot add up because you cannot add the letters in the alphabet.
so the letters A and B must be describing the momentum of the 2 objects.
so if you were to describe the resultant force due to a collision of 2 objects which words would you use.
the force of momentum.
or what?
Quote:
because it started with 2 units of momentum only in different directions and because the pipe is moving towards the mass the pipe may accelerate the mass even further as the pipe stops.
No no, absolutely not. Momentum is a vector. So when you add momentums you have to do vector addition. In 1D that means -1 + +1 = 0. It does not mean |-1| + |+1| = 2. No way.
Im begining to wonder if you have a clue as to what happens in the real world.
when I said 2 units of momentum that is exactly what I meant.
the pipe has 1 unit , the mass has 1 unit , when they collide the collision will be the product of the 2 units of momentum.
is there a zero in your vector addition?
do your vector graphs have a zero?
do a vector graph of your car going from 0 - 10 mph
then the car goes from 10 - 0 mph
then the car is put into reverse and backs up from 0 to -10 mph
I want to see if you really believe yourself.
