Originally Posted By: paul
ok , lets do the rest from outside then.

OK. I probably should have mentioned that sooner.



Quote:

now you only have -2715.853 Ns vs +77048.82 Ns
thats a difference of
+74332.967 Ns momentum


Again, you've ignored the other 49 masses that are about to hit the turn. They're more than enough to stop the pipe then reverse its direction.



Quote:
if so I suppose that the "d" in the formula has no real value because so far I havent been able to find just what is used to put where the "d" 's are. !!!

I think we should leave that for another time. The d has a common meaning that's universally used across math and physics, so they don't need to say it. It's much more standard than symbols for velocity, etc. But we better not go into what it actually means. Easier to just not use that formula.


Quote:



m1 vi -27.15853 m/s
m2 vi +12.84147 m/s

m1 mass 100 kg
m2 mass 6000 kg

results

m1 v = +51.52999459 m/s
m2 v = +11.52999459 m/s

is that about what you get?

do you think that this would be a good way to determine the
velocity of the 100 kg mass as it leaves the turn and the velocity of the pipe?


Yes to all the above. Except I don't trust the vi values you're using. But that's an issue with the accelerator not the turn.