Originally Posted By: paul
Quote:
After that 1s, I'm still applying the same 80N force, continuously for all the seconds up to 50.


if you wanted to determine the total force that you applied
in the above how would you put the above into a equation?

What does "total force" mean? If it means force * time, then the usual name is "impulse".

Deny the name if you like, but when you multiply a force by the time it's applied for, you're calculating an impulse. See Wikipedia.


In your gas example:
(1) The rate of decrease of volume = 20gallons/second
The total volume burnt is
(2) volume = 20gallons/second * 50 seconds
volume = 1000gallons

Notice how we didn't start with a volume, but a rate of change of volume (gallons/second, not gallons).



Anyway, we really have to stop wasting time until you use units correctly. Just treat them the same as numbers or algebraic variables:

2x * 3x = 6x^2 ( that's 6*(x^2) )
2m * 3m = 6m^2 (like measuring the area of a room)

2x * 3 = 6x
2N * 3 = 6N

2x * 3y = 6xy
2N * 3s = 6Ns
2gallons * 3seconds = 6gallon-seconds

2m/s * 3s = 6m
2gallons/second * 3seconds = 6gallons
2kg.m/s/s * 3s = 6kg.m/s