1-v^2/c^2) = 0 or a number lower than c.
(1-1^2/1^2) = 0
(1-299,792,458 m/s^2 / 299,792,458 m/s ^2) = 0
in the example above the velocity is c
yet the math reduces the velocity to below c.
Paul, That actually looks just exactly right. Although you seem to be slightly misinterpreting the result. What this leads to in the total equation is that you find that you wind up dividing by zero. This of course is not allowed, because it means that your answer is: x/0 = infinity. So the mass m becomes infinite. Since it would take infinite energy to accelerate anything with a mass m_0 greater than 0 to a speed of C then you can't do it. Since light has an m_0 = 0 then you wind up with the mass m still = m_0, or 0. In this case you are still dividing by zero, but what you are dividing by zero is zero, that is; 0/0 = 1, because any number divided by itself is 1. And any number multiplied by zero is zero.
I'm not sure where you are getting the idea that the speed is reduced below C. In fact the speed is canceled out in the division and you have a dimensionless number. There is no speed in the answer, all you have is mass.
Bill Gill
