Is the system sealed? If so then the HHO can't float up because there's no denser fluid (air) floating down to displace it.

yes the system is sealed between the point where the HHO is generated and the point where the HHO is used as a fuel.

I forgot to include this in the image but the larger pipe
(B2) has air inside it , thats why its larger.

the HHO rises through the air due to its density.
air cannot flow through the pipe (B1) because of the
pressure inside (A1).

and because HHO is lighter than air the HHO will gather at the top of (B2).

the HHO that gathers at the top in (B2) also acts as a
storage area where more HHO can be drawn off when needed
for power surges in the power plant.

depending on the type of power plant you are using
ie.. if using a ICE engine or turbine then you would mix air with the HHO at the top after the HHO has passed through (B3).

unless you have a ICE or turbine that uses only HHO.

for a fuel cell you would not want a mixture.
but you would need a seperator to seperate the hydrogen from the oxygen.

but thats not really a part of this recovery system as it can vary greatly.

but if you were to need to build one that doesnt use a pipe that uses air to raise the HHO , and need to determine the difference in weight of the two
( air and HHO ) I have provided this below.

According to the CRC Handbook of Chemistry and Physics, the density of dry air at 20 degrees C at 760 mm of mercury (one atmosphere of pressure) is 1.204 milligrams per cubic centimeter.

1 cubic foot = 28,316.8467 cubic centimeters.

So, dry air weighs 34,093.48 mg per cu.ft.

Which is about 1.2 ounces per cu.ft.

if the pipe had a cross sectional area of 1 entire sq inch
this means that 144 feet of pipe could house 1 cu/ft of air or HHO at any given time.

so if the pipe is 144 feet tall then there would be a need to supply a force of 1.2 ounces , well not that much.

as HHO weights less than air.
1 cu inch of air weighs .00004 pounds
1 cu inch of HHO weighs .00002 pounds

1 cu ft of water weighs 62.4 lbs
1728 cu inches in 1 cu ft
62.4 / 1728 = .0361 lbs
1 cu inch of water weighs .0361 lbs

water expands 1800 times when converted into HHO
1 cu inch of water weighs .0361 lbs
so 1 cu inch of HHO weighs .0361 / 1800 = .00002 lbs

there are 12 inches x 144 ft of HHO in the pipe so it
weighs (12 x 144) x .00002 lbs = 0.03456 lbs


so for every 144 feet in height you would need to supply a
constant force of .03456 lbs in order to get the HHO to go into the pipe at the bottom.

I think we'll be running in circles until we can quantify it.

well that has that pretty much quantified wouldnt you say

Or just build one! Look how cheap and simple it is!! Some bits of wire in a pipe, a water wheel, an old lawnmower motor and an alternator from the car wreckers.

I think that building something should follow design work
after all you need to know how much electricity your system would use in producing HHO in order to design a proper recovery system to recover that electricity.

then theres the percentage that you want or need to recover
if you only want to recover the 22% lost durring conversion to HHO then the system could be much smaller.

if your providing hydrogen for the space shuttle or commercial air lines then your system would need to be much larger.

3/4 inch of dust build up on the moon in 4.527 billion years,LOL and QM is fantasy science.