Yea I suppose I didn't really explain it properly.
Originally Posted By: paul
does the 3200 mean 3200N?
Yes. That's the peak force, occurring in the middle of the motion.
your diagram should look more like a big "M" instead of
a mountain.
the largest forces your showing as resultant forces
dont have anything to result from.
the 4000N is zero at 1 second , you must have the program
wrong somewhere.
That's also where the horizontal 1500N (average) reaction force occurs.
that 1500N average would also be wrong.
Yep, the 4 bottom elements are all prevented from moving vertically, but free to slide sideways.
so the torque is present.
and there is a matching F3 force , that is striken then.
It's a general purpose program I used. No, that's one of the weaknesses. It assumes the digonal linkages have the same fixed angle when finding the forces, tho is does have them moving. The springs compressed a fairly spectacular amount, but that would just be because I made the dimensions quite small. If it were all scaled up a lot, there'd be hardly any movement of anything (relative to the size).
whats the name of the program?
can it be downloaded?
I would like to plug in your numbers to see what results I
can get from it using different spring constants.
Yes. 3200N on each leg. So 6400N total. Of course that's only the maximum and only occurs for an instant. Most of the 2s are spent at less force.
you must be using only 2 legs , thus the 6400N
that couldnt be the result from a force of 4000N
applied at a angle of 45 degrees.
The average is 2000N/leg. Which is really quite close to the 4000N total I've been saying all along :P
we'll just have to wait and see , I think your program
doesnt include the proper elements or you wouldnt get
such large reaction forces when there are no action forces
present.
