I cant seem to find any use for a free body diagram
its more like filler for physics books , and lecture times.
were you going to use one to show that there really are no
forces involved?
just say 1-1=0 and 1-1=0 then your done.
all they do is show the exact reverse of a force.
you apply a force
at -0
and the same force is applied back
at +0
whats the point?
If it's stopping in 1s then it's an average of 4000N.
no its not , use the force kallog.
F = ma
unless f=ma is wrong , are you saying that?
you must be trying to average something out again , trying to get an angle on it.
I suppose that since the 100kg mass was accelerated for
8 seconds then its average would be 500N right?
so I suppose you could say that the average could be only
2000N if you had an extra second , but you only have 1 to work with.
but if you cut the second in half you could get 2 1/2 seconds , this way you could get an average of 2000N
over the 2 1/2 seconds.
nope that wouldnt even be right you would still have
4000N because a Newton is measured in seconds not 1/2 seconds.
I guess I should elaborate on that 1N = 1kg meter/s^2
to avoid the comments from the peanut gallery.
a force that will accelerate a mass of 1 kg
at a rate of 1 meter per second per second.
if you cut the second in half it is only half the newtons.
If it's changing direction in 1s then it's an average of 8000N.
it changes direction in 2 seconds not 1 second.
so its not 8000N its 4000N
I will re-post that part.
since Im no longer turning the mass around , the only force
I must overcome is 4000N , the 100kg mass can be accelerated
to 40m/s velocity in 1 second and it will travel a distance of 20 meters in that 1 second.
so stopping the mass requires that exact same force applied in the opposite direction in that same time.
f=ma
4000N = 100/40
a=f/m
40=4000/100
in 1 second the mass stops.
it will not require 8000N
to stop the mass in 20 meters and 1 second
