Originally Posted By: paul

I believe if I use a 180 degree turn I can divide the
1 second by 180 , since the mass is traveling in a circular path I can use the linear angle and the fc angle to find the amount of linear force for each degree of rotation , then add up the forces as I said before.

Sound like a plan. I've added them all up as you suggest using a spreadsheet instead of a questionable simplification.

I used the equation in my previous message:
F_longitudinal = F_outward * cos(theta)

You can see that with coarse 10 degree steps it isn't quite 8000N, but the smaller the steps the more it approaches 8000N.