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Secondly, at the start of the article it s conjectured that local gravity could be caused by remotely rotating matter
When you read bullshit you should entertain no delusions of it being a model of physical reality. How much longer will you remain willfully stupid? All the spins in the universe at all scales algebraically sum to zero. It's a boundary condition. If this were not true the excess could be trivially measured with three orthogonal gyroscopes,

http://www.spie.org/web/oer/september/sep96/gyro.html
http://arXiv.org/abs/gr-qc/0206033
Rep. Prog. Phys. 60(6) 615 (1997)

Permanent magnets have polarized electron angular momenta. They display no gravitational anomalies to at least one part in ten trillion difference/average. 94% of the Alnico 5 magnetic field originates in electron spin versus 63% in Sm2Co17 where the balance is from electron orbital angular momentum.

http://www.npl.washington.edu/eotwash/spin1.html

That test mass has 10^22 net polarized spins. One side does not have a different gravitation than the other. The universe is homogeneous and isotropic.

Superconducting magnets are a favorite charlatan's fetish. Two pairs of anti-parallel fused silica balls spinning at 4300 rpm are contained within a fused silica housing spinning at 0.7742 rpm in Gravity Probe B. The balls are coated with a thin layer of niobium cooled below its superconducting transition temperature. They all gravitate identically, F=GmM/r^2 in orbit.

Nothing can spin faster than a millisecond pulsar and stay together. As exquisitely explained in my prior references, NONE of which you read, you persevarative jackass, pulsars gravitate by the book.

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Finally let me say that the ideas brought forth in the mentioned article as a whole are in my view a bold kick-off in the long lasting attempt to unify quantum theory with relativity.
A unifying theory must have c=c, G=G, and h=h simultaneously; not approximate c=infinity (Newton) or G=zero (quantum field theory), or h=0 (General Relativity). Your hairball exercise in crackpottery ain't it, git.

Screw your butt into a chair and learn something about spinning bodies:

The limiting equatorial velocity, for a rotating sphere (and this velocity is independent of the size of the object) is given by

v_lim = sqrt(2*S/rho)

where S is the yield strength and rho the density. The strongest non-degenerate material, diamond, is 10 tonnes/mm^2 which translates to about 10^11 Pa (100 gigapascals). Diamond density is about 3500 kg/m^3. Put this into the formula,

v_lim = 7600 m/s (approximately)

i.e. 4.7 miles/sec. Check the math. Now look up the strength of nuclear matter for a neutron star's neutronium, density = 2x10^17 kg/m^3, and plug in the numbers.

This is based on evaluating the forces acting on a surface element with area "dA" of the rotating body. Given an infinitesimally thin surface element the only stresses acting are tangential since radial stresses go to zero on the surface. Said tangential stresses still yield a radial force component for a curved surface. It is a general result from the theory of elasticity (first by Laplace, but easy to rederive on the back of a small envelope) that given a surface element with area "dA" and thickness "dt", with tangential stresses present in the surface, the normal (to the surface) force acting on this element is

dF_s = (S1/R1 + S2/R2)*dAdt

where "R1", "R2" are the main radii of curvature of the surface (at the point of evaluation) and S1, S2 are the stresses along the directions of the corresponding axes of curvature).

Take our ball rotating with an angular velocity "w" and evaluate the forces acting on an equatorial surface of element. For convenience the evaluation is done in the rotating reference frame. In this frame, the surface element is acted upon by two forces. First, there is the elastic force, described above, which simplifies to

dF_s = (S1 + S2)*dAdt/R

since R1 = R2 = R, the radius of the sphere. This force is pulling the surface element inwards, towards the rotation axis. The second force is the centrifugal one

dF_c = R*w^2*dm

where dm is the mass of the suface element, given by

dm = dAdt*rho

where rho is the density. So, we get

dF_c = R*w^2*rho*dAdt

And this force acts ouwards, away from the rotation axis. Since the surface element remains stationary in the rotating frame (until the sphere is driven to disintegrate) the two forces dF_s and dF_c must be equal. So, we've

R*w^2*rho*dAdt = (S1 + S2)*dAdt/R

Cancelling the common factors and reorganizing we get

(R*w)^2 = (S1 + S2)/rho

Now, R*w is simply v, the velocity of the equatorial point. As for S1 and S2, neither of them can be larger than the tensile strength S. So, you get

v^2 less than or equal to 2*S/rho

with the = sign obtaining at the limit, before the material gives. This is the relationship used above to find the limiting velocity. Note that the radius cancels.

The ratio S/rho, which has the dimensions of energy/mass can be simply interpreted as the binding energy per unit mass of the material. The result is interpreted as the ball holds together as long as the kinetic energy per unit mass (in any locality) is no larger than the binding energy per unit mass.


Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/qz3.pdf