Ok here is what you are working out
https://hannibalphysics.wikispaces.com/Ch+2+Free+FallLet me take each movement individually maybe the penny will drop then
Lets just look at the horizontal first its dead easy. I have a horizontal velocity of launch of 3m/s. So every second it goes away from the cliff 3m. If the drop takes 5 seconds it must land 15m out from the cliff and it will still be going at 3m/s.
The x value of the calculus is that number m*t and it matches for every value.
The vertical movement is a bit trickier because the rock accelerates. Without going to elaborate detail there exists a solution called Newtons second equation of motion which gives you the distance over time. The equation removes the need to worry about calculating the intermediate velocities.
http://aphysicsteacher.blogspot.com.au/2010/02/newtons-second-law-of-motion.htmlS = ut + 1/2at2That is what the y coordinate is.
I am totally lost where you are getting velocities from the function doesn't calculate them its calculating distances.
I have hidden a lot of maths including the velocities behind the background which is why you use calculus.
Added: Here the
blue ball plot is what we are making the 2D coords (x,y)for each time
Do you get it now the horizontal and vertical need different equations.
