I am trying to understand your gibberish as best that I can
function X = function(mt, ut + 1/2at^2);
function Y = function(-mt, -ut - 1/2at^2);
using v = 10 mps
using t = 5 sec
mt, ut + 1/2at^2
10 x 5 , 10 x 5 + .5 x 9.8 x 5 x 5
50 , 50 + 122.5
replacing your comma with math opperator symbols.
comma as addition
[+50] + [+50] + 122.5 = +222.5
comma as addition
[-50] + [-50] - 122.5 = -222.5
comma as subtraction
[+50] - [+50] + 122.5 = +122.5
comma as subtraction
[-50] - [-50] - 122.5 = -122.5
comma as multiplication
[+50] x [+50] + 122.5 = +2,622.5 <----
comma as multiplication
[-50] x [-50] - 122.5 = +2,377.5 <----
comma as division
[+50] / [+50] + 122.5 = +123.5 <----
comma as division
[-50] / [-50] - 122.5 = -121.5 <----
which is why I asked you what the comma was used for.
again what does the comma represent?
