Ok Paul, How fast am I falling towards the center of the Earth?
if you were sitting on the roof of your house.
and if you were 4000 miles from the center of the earth and on the equator.
then the circumference of the 360 degree circle that you are traveling in as the earth rotates would be 25,132 miles.
4000 x 2 = 8000 miles diameter
8000 x 3.14 = 25132 miles circumference.
you have a angular velocity of 1047 mph.
25,132 miles / 24 hours = 1047 mph.
in one second your angular displacement is 1535 ft/sec.
if gravity became a republican, and just decided to stop doing its job because it wanted more tax cuts and tax breaks and give aways
to the top 1% , and gravity was not accelerating you towards the center of rotation like is should be doing , then you would launch
at a 90 degree angle away from the center of the earths rotation.
at a velocity of 1535 ft/sec
gravity is pulling / accelerating you at a rate of 32.2 ft/s^2
that doesnt mean that you are falling that fast , thats just how fast that you would fall and accelerate as you are falling if there were nothing stopping you from falling.
your not being pushed down like some of your bone headed colleagues seem to think
http://wiki.answers.com/Q/Does_gravity_pull_things_down_32.2_feet_per_second Gravity is NOT a pulling Force. Gravity is a "Pushing" Force of Mass Expansion.
Earth Mass is Expanding at the Gravitational Acceleration rate of 9.808175174 m/s^2
In order to understand you must first accept the Mathematics on Einstexxxxxxxxdotcom because Math does not lie. Then you can move on to
he doesnt even konw how to calculate the acceleration due to gravity in the first second , he thinks theres instant acceleration durring the first second of acceleration due to gravity. LOL
ie...
After one second, the ball will be traveling 32.2 ft/s. After two seconds, it is traveling 64.4 ft/s, and after three seconds, it is traveling at 96.6 ft/s.
