now that all depends if you can move a distance
ok , then we can move a distance and that distance can be moved at 3 m/s
what force would you use to move a distance?
what is the mass of a distance so that I can determine the amount of force required to move a distance?
you used 5 meters * 3 m/s^2
how much mass is in 5 meters?
We can multiply any two quantities
then 5 dollars * 3 m/s^2 = ?
can you multiply 5 dollars x 3 meters?
would that be 15 dollar-meters
You actually don't know why the units get squared do you?
m/s^2 = meters per second * meters per second
or
m/s^2 = meters per second per second
an object accelerating at 3 m/s^2
accelerates 3 meters every second.
after 1 second its speed is 3 m/s
after 2 seconds its speed is 6 m/s
after 3 seconds its speed is 9 m/s
so something that is accelerating at a rate of 3 m/s/s
should accelerate to a speed of 3m/s*3m/s=9 m/s in the 1st second
its just another case of flawed logic.
meters per second * meters per second !!!
you dont need to square meters or seconds.
an acceleration of 3m/s = an accelerating object that accelerates 3 meters each second
an object that has a speed of 3m/s = an object that has a speed of 3 m/s each second
unless its not that the meters are squared and only the seconds are squared.
as in meters per second divided by seconds
that would make sense.
because 3m divided by seconds can even show that it is right
an object accelerates at 3m/s for 4 seconds
ie...3ms/4s
you know its speed from the 3 and 4
3*4=12 m/s
but squaring meters is stupid.
as in googles 8.6856blablabla
m^2/s^2 is stupid