Science a GoGo's Home Page Forums General Discussion Physics Forum Long rope and mass = DOPPLER EFECT

I have been baned many time from many forum
many people use Einstein without classical mechanc base
it is huge problem to see doppler efect but we can do this very easy

Why I want done this ( please read befor click link )

GALILEO STARTED
WINDOWLESS ROCKET PROBLEM
Many authors repeat below words as a famous problem ( I copy below words)

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" Imagine an observer traveling inside a windowless spaceship moving away from the sun at constant velocity. Galileo asserted that there are no mechanical experiments that can be made inside the rocket that will tell the occupants that the rocket is moving . The question ``are we moving'' has no meaning unless we specify a reference frame (are we moving with respect to that star'' is meaningful). This fact, formulated in the 1600's remains very true today and is one of the cornerstones of Einstein's theories of relativity. "
...
"Einstein’s theory was based on two key principles:

1 The principle of relativity: The laws of physics don’t change, even for objects moving in inertial (constant speed) frames of reference.

2 The principle of the speed of light: The speed of light is the same for all observers, regardless of their motion relative to the light source. (Physicists write this speed using the symbol c.) "

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http://tesla8.blogspot.com/ ( one rope and mass m experiment )

http://tesla64.blogspot.com/ ( first internal doppler IDEA)

http://tesla32.blogspot.com/
( Independent to above light test )

Your Rope Mass and Dynamite epxeriment is so complicated that I gave upB trying to understand what it is You arevtrying to prove.

thank ing you blobby2

Your rope experiment is flawed - you're using kinetic energy where you should be using force, calculating kinetic energy when you should be calculating work, and assuming instantaneous acceleration (which doesn't occur in the real universe).

Lets calculate things correctly, using actual newtonian physics:

Lets start with you your 1kg mass moving at 1m/s, and lets assume everything happens in 1 second. To slow to 0m/s in 1 second requires an acceleration (a) of:
a = deta(v)/t
a = (-1m/s)/1s
a = -1m/s2 (negative indicates direction)

The force required for this acceleration is determined by F=ma:
F = 1kg*(-1m/s2)
F = -1N

To accelerate from 1m/s to 2m/s in one second requires the same acceleration, but in the direction of travel:
F = 1kg*(1m/s2)
F = 1N

So the force required to accelerate or slow the same mass by 1m/s in 1 second is the same (1N); only the direction of the force changes.

To determine the energy required for the acceleration you need to calculate work. Work is force * distance.

Distance during acceleration is: d = Vi * t + 1/2 at2
For slowing:
d = (1m/s * 1s) + 0.5(-1m/s2 * 1s2)
d = 1m + 0.5(-1m)
d = 0.5m

For accelerating:
d = (0m/s * 1s) + 0.5(1m/s2 * 1s2)
d = 0m + 0.5(1m)
d = 0.5m

So, in both cases, the 1kg mass travels 0.5m while accelerating/slowing. This means it takes an equal amount of work (energy) to slow or accelerate by 1m/s in 1s. In either case:

W = F*d
W = 1N*0.5m
W = 0.5J of energy

So your blog post is wrong - in a windowless spaceship, a mass accelerating or slowing in the ship will require the same force and work (energy), regardless of the direction of travel relative to the spaceship. Given that, its hard to take the other blog posts seriously.

Bryan