And Paul, either way, with or without “t” in the denominators, of v and c,
there is still the t (time in seconds) in front of the square root sign.
Time is still used to calculate the dilated time.
v2/c2 results in units of (distance) and (meters)/(seconds)
ie...
1 m/s ^2 / 10 m/s ^2 = .01 m/s ^2
you then subtract the result that is given in (distance)
and the rate of change over time (m/s) from the 1 that causes
the result to always be lower than 1
1 - .01 = .99
this leads us to your point below.
there is still the t (time in seconds) in front of the square root sign.
the square root of .99 is 0.99498743710662
so the current calculation is 0.99498743710662 m/s
it is a amount of velocity it has not been converted
into an amount of time.
its not simply a number nor does it only have units
of time attached to it.
remember this:
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time.
in other words if you multiply 2 apples x 2 oranges
you still only have 2 apples and 2 oranges.
you dont have 4 apples or 4 oranges.
you cannot convert apples into oranges.
and you cannot convert velocity into time.
by multiplying the 1 second in the calculation
that you pointed to times the current
total in the calculation of 0.99498743710662 m/s
1 s * 0.99498743710662 m/s = 0.99498743710662 m/s
the above is not what the equation would have us expect
to be possible , the equation expects us to simply believe
that the result will be converted into time.
but you cant multiply an amount of time by an amount of velocity and have the result given in an amount of time.
1 second * 1000 m/s is not equal to 1000 seconds
so nothing changed !!! time has not yet been changed
nor has velocity been converted into time.
the result is not an amount of time.
the result of the equation is still a velocity.
and since 1 second * 1 second = 1 second the time
never changed it is still 1 second.
now if the 1 second were 2 seconds then thats another
story all together because the 2 seconds would then
be multiplied by the distance in the 0.99498743710662 m/s
and the result would become 1.98997487421324 m/s
once again you cant multiply an amount of time by an
amount of velocity and have the result given in an amount
of time.
or at least I cant.
Why again don’t you think the equation is true?
because I can (think).
trying to work with this 1 inch x 2 inch reply box
is really hard to do.
so I make lots of mistakes that I have to correct.
it takes me awhile to make a decent reply.
but I think I get my point across most of the time
even if it never sinks in.
