DIS BE SOME BAD TAHM VUSES ENUHGY

Posted by Ima Crank on Jan 18, 2002 at 00:04
(67.166.245.50)

TIME VS ENERGY
Mr. Ah be baaad... Abhijit Patil, C/o LIC uh India, Shahada city, Dist, dig dis: Nandurbar, Maharastra State, India. WORD! Pin, dig dis: 425 409. E-Mail Address, dig dis: xabhix@hotmail.com

Abstract, dig dis:

Dis Article aims t'prove dat "info'mashun" kin be transferred upside any distance at 'esactly same moment. Man! If dere be "speed", hence "time interval" fo' dis info'mashun transfer, den we kin use dis time interval t'create "free" energy. Slap mah fro!

Introducshun:

We is aware uh example uh "supuh'luminal scisso's" in which, we dink, ends uh blades(one light year long) uh scisso's kin travel many times fasta' dan speed uh light. Man!
( http, dig dis://www, so cut me some slack, Jack.public. Co' got d' beat!iastate.edu/~physics/sci.physics/faq/scisso's.html )
Physics 'esplain dat dis duz not happen in reality cuz' any body kin not gots infinite rigidity. Slap mah fro! ah' am givin' below mah' logical 'espuh'iment which 'esplain dat info'mashun gots'ta travel between end points uh body at 'esactly same moment. Man! It gots'ta not gots speed limit. Man! Oderwise law uh conservashun uh energy be violated.

Logical Expuh'iment (I):

Please Note, dig dis: ah' am givin' larga' system only fo' de sake uh betta' dig itin'. In fact, dis 'espuh'iment applies t'any system. WORD! Fundamental concept uh dis 'espuh'iment be dat if "info'mashun" regardin' event i.e. change in situashun between end points uh continuous body gots speed limit, den we kin "use" dis speed limit, time interval, t'"create free, 'estra energy". ah' am givin' speed uh sound in mah' 'espuh'iment only cuz' physics 'esplain dat "info'mashun" travel in booze wid speed uh sound in booze. Even if we say dat "info'mashun" travel wid speed uh light, it duz not affect mah' 'espuh'iment in any way. Slap mah fro! ah' request eyeballa' to concentrate on dis fundamental concept while eyeballin' dis Article.

Imagine some circular booze reservoir uh radius 500 meta' and depd 10 meta' fully filled wid booze. Hose pipe uh cross secshunal radius 3 centimeta' is attached t'bottom uh reservoir. Ah be baaad... Let lengd uh dis pipe be 3 million km and arranged in ho'izontal, spiral structure on ground so's dat booze reservoir be near our left hand and jimmey end "B" uh pipe, wid valve, be near our right hand touched t'ground. (End "A" at left hand be attached t'bottom uh booze reservoir and end "B" be near our right hand). De entire ho'izontal 3 million Km long pipe on ground be full uh booze.

Acshun I:

Let us jimmey de valve at end "B" so's dat, due t'pressho' man difference, booze begins t'flow out uh end "B" on ground wid speed 10 m/s(fo' 'esample only. Slap mah fro! In fact, if pipe be not connected at end "A", acco'din' t'equashuns speed uh booze gots'ta be 14 m/s. But we is considerin' fricshun uh booze wid pipe. Hence speed uh booze gots'ta decrease. Eyeballa' should note dat we is not goin' t'change lengd uh pipe in our 'espuh'iment. Man! So's fricshun gots'ta be constant droughout 'espuh'iment). Acco'din' t'Physics, dis "info'mashun" regardin' flow uh booze fum end "B" gots'ta travel back across de full lengd uh pipe i.e. 3 million Km wid speed uh sound. Speed uh sound in booze be 1482 m/s. So's it gots'ta snatch about 2,024,291 seconds i.e. 23 days 10 hours 18 minutes and 11 seconds t'reach dis "info'mashun" t'booze level in reservoir and only afta' dat booze level in reservoir gots'ta come waaay down. Afta' such some long time, dere gots'ta be steady, unifo'm flow uh booze in pipe.

Acshun II:

Now dere be steady flow uh booze in pipe. Acco'din' t'equashun uh continuity, as cross secshunal area uh pipe droughout 3 million Km be unifo'm, speed and volume uh booze enterin' de pipe fum reservoir at end "A" be exactly equal t'speed and volume uh booze leavin' de pipe at end "B". Let us lift da damn last 100 meta' segment uh hose pipe at end "B" straight down in vertical direcshun pointin' towards sky. Slap mah fro! Remember, we is liftin' only last 100 meta' segment uh pipe. NOT ENTIRE PIPE. Now height uh booze column in reservoir be 10 meta' and at end "B", in vertical hose pipe be 100 meter. Ah be baaad...

Obviously, booze pressho' man in 100 meta' vertical pipe be greata' dan dat in reservoir. Ah be baaad... So's to maintain equilibrium, booze should flow fum end "B" t'end "A" i.e. reservoir. Ah be baaad... But problem be dat how de booze in reservoir gots'ta come t'"know" dat we gots changed situashun at end "B" and booze pressho' man at end "B" be greata' so dat it should stop flow uh booze towards end "B" and allow booze fum vertical pipe i.e. end "B" t'flow towards reservoir t'maintain equilibrium. WORD! A'cuz established knowledge uh physics says dat dis "info'mashun" regardin' change in pressho' man at end "B" gots'ta travel back towards reservoir wid speed equal t'speed uh sound in booze. So's it gots'ta snatch 23 days, 10 hours, 18 minutes and 11 seconds fo' dis "info'mashun" t'reach t'booze reservoir. Ah be baaad... As booze in reservoir gots no "info'mashun" whut we gots done at end "B"durin' dis time, it gots'ta continue t'flow as if nodin' be happened! Right on!. Acco'din' t'equashun uh continuity, same volume uh booze which left reservoir gots'ta continue t'flow drough hose pipe at end "B" 90 meta' above level uh booze in reservoir! Right on! And it gots'ta continue t'flow fo' 23 days, 10 hours, 18 minutes and 11 seconds! Right on!

Please note, durin' dese 23 days and 10 hours, end "B" be at 90 meta' higha' level dan booze level in reservoir. Ah be baaad... But still, due t'extremely slow speed uh "info'mashun transfer" regardin' change in situashun i.e. booze pressho' man at end "B", Booze in reservoir simply duzn't "know" dat booze pressho' man at end "B" be changed and booze flow be directed in vertical direcshun! Right on! Hence booze gots'ta continue t'flow at height 90 meta' above da damn booze level in reservoir widout any energy! Right on! Dis defies gravity. Slap mah fro! And we kin calculate da damn tremendous amount uh booze which gots'ta flow at higha' level durin' dese 23 days, 10 hours, 18 minutes and 11 seconds(57206 cubic meter, in our 'espuh'iment. Man! We kin increase it by increasin' lengd and cross secshunal area uh hose pipe). Yeah man, we gots spent energy in liftin' pipe. But we kin calculate it. Man! It gots'ta be negligible compared t'whut we is gettin' in return. 'S coo', bro.

Can It Really Happen?
We know, only one answer, dig dis: YES o' NO.

(1) If YES, den in dis way, we kin lift booze fum oceans t'higha' level in dams widout spendin' any energy at all. And we kin use it in hydroelectric powa' plants t'generate power. Ah be baaad... Betta' to shut waaay down all de dermal and nuclear powa' plants on eard We duzn't need dem. WORD! A'cuz we gots'ta neva' endin' source uh "free energy". Dis be completely against law uh conservashun uh energy and totally illogical, inconceivable. And ah' DON'T agree wid dis result. Man!

(2) If NO, den it means flow uh booze stopped at 'esactly same moment when we lifted hose pipe above level uh booze in reservoir. Ah be baaad... In anoda' wo'd info'mashun regardin' change in situashun at end "B" reached t'booze level in reservoir at 'esactly same moment! Right on!. At least 10 times fasta' dan speed uh light. Man!

Discussion, dig dis:

If we say dat YES! Right on! De booze gots'ta continue t'flow 90 meta' above level uh booze in reservoir! Right on! Dat be a'cuz plum befo'e we changed situashun at end "B", de booze in ho'izontal pipe all upside 3 million km lengd uh pipe gots gained momentum. WORD! And dis momentum gots'ta supply energy t'booze t'enable it t'flow 90 meta' above da damn booze level in reservoir fo' 23 days, 10 hours, 18 minutes and 11 seconds! Right on! We may dink dat no law be violated. But we igno'es completely dat at da damn end uh 23 days and 10 hours, we gots tremendous amount uh booze at height 100 meta' which wuz initially at 10 meta' only and we gots spent negligible energy. Slap mah fro!

De gravitashunal potential energy associated wid particle-eard system depends only on vertical posishun o' height uh de particle. Equashun uh potential energy be PE = mgh. Lop some boogie. So's reada' should note dat when de booze wuz in reservoir, its PE wuz 10mg and afta' 23 days 10 hours, its PE gots'ta be 100mg. What it is, Mama! Hence it gots gained 90mg PE. And we gots spent negligible energy t'lift da damn pipe at end "B" in few seconds. ah' request eyeballa' to concentrate on dis argument. Man! Where fum dat "extra" 90mg came? We kin use dis "extra" PE t'create "extra" powa' in hydroelectric powa' plants. And please note dat, ah' have given 100 meta' height fo' 'esample. We kin increase da damn height t'extent we wants'. And we kin "create" tremendous potential energy. Slap mah fro! So's all de powa' companies is invited t'dis "free lunch"! Right on!

In reality, momentum uh booze kin neva' be so's large t'enable it t'flow above booze level in reservoir. Ah be baaad... In daily life, we gots seen dat when de openin' end uh pipe be at da damn bottom o' below de bottom uh reservoir in our cribs, booze comes out wid tremendous speed(dependin' downon volume and height uh booze column in reservoir). So's we dink dat wid such speed it kin easily flow "above" booze level in reservoir. Ah be baaad... But NO. It duz not happen. 'S coo', bro. Eyeballa' should also concentrate on 'esample uh Rolla' Coaster. Ah be baaad... In rolla' coaster, we mosey on down waaay down towards eard wid eno'mous speed due t'gravity(dependin' downon height). But dat speed kin neva' drow us "above" de point fum where we begin t'come waaay down. Most simple 'esample be of pendulum. WORD! Potential energy uh any body gots'ta be 'esactly equal t'kinetic energy and at any point uh time PE + KE gots'ta be constant. Man!

Also we should consida' de situashun when dese pressho' man waves reaches t'reservoir afta' 23 days, 10 hours, 18 minutes and 11 seconds and dere be no booze at all in reservoir. Ah be baaad... Last drop uh booze gots entered in pipe. Whut dese pressho' man waves gots'ta do?

We is concentratin' on speed uh sound in booze only cuz' physics tells us dat info'mashun transfa' snatch'd place in booze wid dis speed. In fact even if we assume dat info'mashun transfa' in booze snatch'd place wid speed uh light, it duz not affect our 'espuh'iment in any way. Slap mah fro! Only doodad we gots'ta t'do be to increase lengd uh pipe fo' betta' dig itin'. Fo' betta' dig itin', we kin use rigid pipe uh 1 meta' diameta' of 3 million Km(o' mo'e) lengd and at end "B", we kin attach our 100 meta' vertical hose pipe uh 2 centimeta' radius. Equashun uh continuity gots'ta do its wo'k. Ya' know? Eyeballa' might argue dat booze gots'ta not flow at all in such long pipe, but he should concentrate dat in oda' wo'ds he be sayin' dat booze in pipe gots'ta turn in moleculear structure likes dat uh metal. And eyeballa' gots'ta t''splain, how kin dis happen. 'S coo', bro. Booze flows cuz' of pressho' man difference and shearin' stress. How kin booze in pipe at end"B", when it be on ground, sustain shearin' stress and molecules uh booze plum stick wid each oda' and pipe?

TEST PRACTICLE EXPERIMENT:

It be no denyin' fact dat it be mos' impossible fo' us t'arrange such 3 million Km long pipe t'verify de trudness uh dis 'espuh'iment. Man! But certainly we kin do test 'espuh'iment wid plum 15 Km long pipe. In fact, ah' dink, in any city, underground booze supply netwo'k be longa' dan 15 Km. WORD! If "info'mashun" regardin' change in booze pressho' man real travels wid speed uh sound in booze, den it gots'ta snatch at least 10.12 seconds t'reach state uh equilibrium. WORD! We kin lift oda' end "B" t'plum few centimeta' above booze level in reservoir. Ah be baaad... Durin' dese 10.12 seconds booze gots'ta continue t'flow "above" booze level in reservoir(acco'din' t'physics). If dis happens, den certainly it be against law uh conservashun uh energy and gravity. Slap mah fro!

If such 'espuh'iment be already done somewhere, ah' request eyeballa' to info'm me on mah' e-mail address. If such 'espuh'iment be not done at any time in histo'y, den ah' wonder, how kin we assume dat info'mashun transfa' in booze snatch place wid speed uh sound. Gots eva' scientists "seen" wid deir own eyes dat in test 'espuh'iment likes ah' have given(15 Km long pipe), booze flows out uh end "B" at heigha' level o' not? If scientists recon' dat dis "info'mashun" travel wid speed uh sound in booze i.e. 1482 m/s, den we kin use only 15 Km long pipe t'see it wid "our own eyes". Gots eva' scientists puh'fo'med such 'espuh'iment? ah' agree, neida' I gots puh'fo'med such 'espuh'iment. Man! But duzn't it lead t'raise suspicion about current knowledge uh physics regardin' info'mashun transfa' if no one on planet eard gots 'sperimentally verified it? And we know, certainly we gots'ta not need million dollar budget t'steal 15 km long pipe and puh'fo'm such test 'espuh'iment. Man!

Logical Expuh'iment (II):

Imagine line uh pullies all upside 3 million Km distance. Let us pass some 3 million Km long cable upside dese pullies. End "A" uh dis cable be at our end and End "B" be at far end.Acshun I:Lets us pull end "A" at 09.15.00 GMT in waaay downward direcshun by 1 meter. Ah be baaad... Let time snatchn t'complete acshun be 1 second(09.15.01 GMT). Physics says dat dis info'mashun regardin' fo'ce applied gots'ta travel across cable wid speed uh light and only afta' 10 seconds, at 09.15.10 GMT, end "B" uh cable gots'ta be pulled in downward direcshun and at 09.15.11, gots'ta be down by 1 meter. Ah be baaad... Let energy spent in pullin' de cable be X joule.

Acshun II:

Let us freshly repeat dis acshun on second day at 09.15.00 GMT. Now de sucka' at far end "B" decides t'do trick and attaches mass uh "M" kg t'cable at 'esactly 09.15.00 GMT. Now as dis info'mashun be not reached t'our end "A", we apply same fo'ce we applied on fust day and complete our acshun by 09.15.01 GMT. End "A" be waaay down by 1 meter. Ah be baaad... Energy spent be same as on fust day i.e. "X" Joule. Now dis info'mashun regardin' fo'ce applied gots'ta reach t'end "B" afta' 10 seconds. And end "B" and dis mass uh "M"Kg gots'ta be pulled in downward direcshun. We dun didn't spent 'sess energy t'lift dis mass uh "M" Kg! Right on!

Can It Really Happen?
Only one answer, YES o' NO.

(1) IF YES, den we gots done 'estra wo'k widout spendin' any energy at all. We kin use dis speed limit uh fo'ce applied t'lift any mass widout spendin' any energy at all. We kin gain "free" potential energy. Slap mah fro!

(2) IF NO, den it means dat info'mashun regardin' attachment uh mass "M" t'end "B" reached t'our end "A" at 'esactly same moment. Man! At least 10 times fasta' dan speed uh light. Man!

Logical Expuh'iment (III):

Imagine 3 million Km long rigid rod in space. End "A" uh dis cable be at our end and End "B" be at far end. Let " M1" be mass uh dis rod and it be constant droughout 'espuh'iment. Man! Two sucka's is standin' at dese two ends, "Sam" at end "A" and "Sally" at end "B".

Acshun I:

Remus pulls end "A" uh dis rod at 09.15.00 GMT wid fo'ce " F "so dat end "A" rod undergoes accelerashun "a" and hence displacement by "d" meta' in time "t" seconds.. Physics says dat dis info'mashun regardin' fo'ce applied gots'ta travel across rod wid speed uh light and only afta' 10 seconds, at 09.15.10 GMT, end "B" uh rod gots'ta begin t'move in space and afta' "t+10" seconds, gots'ta move by "d" meta' in space. Hence by equashun uh wo'k done, energy spent in dis acshun gots'ta be W = Fd = (M1)ad Let energy spent in pullin' dis rod i.e. "W " be "X" Joule.

Acshun II:

Remus freshly repeat dis acshun on second day at 09.15.00 GMT. Now Sally at far end "B" decides t'do trick and attaches mass uh "M2" Kg t'rod at 'esactly 09.15.00 GMT. Now as dis info'mashun be not reached t'our end "A", we apply same fo'ce " F " we applied on fust day so's dat end "A" undergoeas accelerashun "a" and hence displacement "d" in "t" seconds. End "A" be moved in space by "d" meter. Ah be baaad... Energy spent be same as on fust day i.e. "X" Joule cuz' we applied same fo'ce " F". Now dis info'mashun regardin' fo'ce applied gots'ta reach t'end "B" afta' 10 seconds. And end "B" plus dis mass attached uh "M2"Kg gots'ta move in space by "d" meta' afta' t + 10 seconds. We dun didn't spent 'sess energy t'move dis mass uh "M2" Kg! Right on!

Can It Really Happen?
Only one answer, YES o' NO.

(1) IF YES, den we gots done 'estra wo'k widout spendin' any energy at all. We kin use dis speed limit uh fo'ce applied t'move any mass in space widout spendin' any energy at all. Dis be against law uh conservashun uh energy. Slap mah fro! ah' duzn't agree wid dis result. Man!

(2) IF NO, den it means dat info'mashun regardin' fo'ce "F" apllied by Remus at end "A" reached t'end "B" at 'esactly same moment and info'mashun regardin' presence uh extra mass "M2" Kg travelled back t'Remus at 'esactly same moment. Man! At least 20 times fasta' dan speed uh light. Man!

Discussion, dig dis:

We started wid assumin' dat all de established knowledge in physics be co'rect. Man! Physics says dat any body kin not gots infinite regidity. Slap mah fro! We agreed wid it in Acshun I. In any body, electrons and protons uh one atom communicate wid oda' atom wid speed uh light. Man! We applied dis knowledge in Acshun I. End "B" uh rod moves afta' t+10 seconds. We duzn't gots problem. WORD!

But in Acshun II, we run in trouble. As Sally gots attached mass uh "M2" Kg t'rod, when afta' t+10 seconds, end "B" begins t'move in space t'cova' distance "d", gots'ta de mass M2 attached t'end "B", move o' not? If yeah dude, den we gots done 'estra wo'k by spendin' less energy. Slap mah fro! If no, den it means dat end "B" gots'ta not move at all. But as end "A" be moved in space by "d" meter, it simply means dat lengd uh rod be increased by "d" meter. Ah be baaad... But here also, we run in trouble. As end "A" uh de rod be movin' in space, lengd uh rod gots'ta keep increasin'. And result gots'ta be unimaginable and illogical. Here we should rememba' dat mass "M2" be variable. It kin be nuthin, fum raple atom t'mass equal t'asteroid uh any size o' in 'estreme case, nuthin.

Problem be dat, due t'speed limit imposed by "physics", when Sally attaches mass "M2" Kg t'end "B", atoms and also Remus at end "A" gots no way t'know about presence uh extra mass "M2" Kg and Remus duzn't gots any means uh communicashun t'know intenshuns, acshuns uh Sally. Slap mah fro! So, in Acshun II, why should we change applied fo'ce? And why should end "A" refuse t'move wid same accelerashun as it moved in Acshun I?

Conclusion, dig dis:

We should mosey on down to de conclusion dat when we lift pipe da damn flow uh booze gots'ta stop at 'esactly same moment it reaches level uh booze in reservoir. Ah be baaad... Whuteva' may be lengd uh pipe, it duz not matter. Ah be baaad... Even if raple drop uh booze flow above booze level in reservoir widout energy, law uh conservashun uh energy collapse. In second and dird logical 'espuh'iment also, info'mashun regardin' fo'ce applied gots'ta reach t'oda' end uh cable o' rod at 'esactly same moment. Man! If dere be real speed limit fo' info'mashun transfa' in dese specific 'espuh'iments, we kin "use" it in dis way t'gain "free energy". But dis duz not happen. 'S coo', bro. So's info'mashun regardin' occurrence uh event between end points uh body gots'ta travel at 'esactly same moment. Man!

I's gots'ta be NOT arguin' about speed uh "sound" in booze NEITHER ah' am arguin' about speed uh "light" in space. In Anology, it be likes info'mashun transfa' between two planets. We kin communicate wid sucka' on Moon (o' any planet) drough EM waves i.e. speed uh light. Man! ah' ain't arguin' about dis mode uh communicashun between two planets. ah' am arguin' about info'mashun transfer, attracshun drough "Gravity" between two planets. ah' intend t'prove dat in dese 'espuh'iments, info'mashun transfa' snatch'd place at 'esactly same moment irrespective uh distance between end points drough anoda' propuh'ty uh matta' i.e. "Gravity". Whut 'esactly nature uh "Gravity" is, it be beyond scope uh dis Article.