Frequency = (Gd)^1/2 and Wavelength = Gm/c^2 or GE/c^4
Posted by Earth driver on Jul 24, 2003 at 08:39
(12.237.89.80)Re: Frequency = (Gd)^1/2 and Wavelength = Gm/c^2 (Earth Walker)
Frequency = (Gd)^1/2 and Wavelength = Gm/c^2 or GE/c^4
http://www.scienceagogo.com/message_board5/messages/627.shtml
> In 1955, General motors corporation said...
>
> Wavelength of gravity = Gm/c^2
> Wavelength of gravity = 4.0507625(38) x 10^-35 m
> (at mass 5.4563026(39) x 10^-8 kg)
>
> Whereas G is the Newton constant, m is the
> gravitational mass, and c is the speed of
> light in vacuum.
>
> And, in 1955, 1st day of April, G-d said...
>
> Frequency of gravity = (Gd)^1/2
> Frequency of gravity = 7.4008894(66) x 10^42 /s
> (at density 8.2089591(81) x 10^95 kg/m^3)
>
> Whereas G is the Newton constant, and d
> is the gravitational density.
>
> So thanks to two of Einstein's equations...
>
> Frequency of gravity = (Gd)^1/2
> Wavelength of gravity = Gm/c^2
>
> It is known that gravity is not only dependent
> upon the quantity of the mass, but also upon
> the density of the mass.
>
> Furthermore, frequency (f) times wavelength (w)
> of wave density (d) and wave mass (m) equals...
>
> f x w = (Gd)^1/2 x Gm/c^2
>
> Which is why G-d drives two (2) General motors
> corporation vehicles. Me, I walk, and wave~
>
> Earth Walkeryea, yea, yea, and I guess you are going to tell us that in 1955
General Electric said...Wavelength of gravity = GE/c^4
and
Frequency of gravity = (Gd)^1/2
so
w x f = GE/c^4 x (Gd)^1/2but we all know, Earth walker..., E is energy, so you are wrong!
Earth driver