Re: thermodynamic laws


Posted by paul on Sep 23, 2003 at 11:43
(65.144.156.109)

Re: thermodynamic laws (Pasti)

then apply the laws correctly and use them to explain
the excess energy in the pipe example.
if there is 528,000,000 lbs of containers moving
in each pipe.

energy in... moving the 200 lbs of water each second.
the short distance between the ends of the pipes.

energy out... moving the 1,056,000,000 lbs of weight represented by the floating containers each second.

ps.. sub technology is not required.
a set amount of cargo weight in each container is.

if you have the ability to do this then I will admit that I
am wrong.

but you cannot do this because I am right so you will not admit that you are wrong.

this can be proven by using a very short pipe cut in half.
say ten feet , sliced down the middle so as to have two haves that will resemble two canals.

if each end is capped before you slice it down the middle
then the two halves will hold water.

you and a friend can now perform a experiment.
place 50 or 60 rubber ducks in each cannal.

circulate the water , if the rubber ducks stay still then Im wrong.

if they move then your wrong.

now expand the cannals to a lenght of 1000 miles.
the same should occur in the expanded cannals.

you will need more rubber ducks.
billions of them in fact.
weigh each rubber duck and multiply its weight ( lbs )
times the distance ( ft ) it moves in one second.
this will give you foot pounds per second.
this is the amount of power that the system is performing
on the rubber ducks.

now multiply this times the number of rubber ducks.
this is the amount of power being performed ( lb-ft/sec)

see if the amount of power being put into the system is the same or higher than the amount of power performed by the system on the moving ducks.

in this case , or experiment there is an advantage and that advantage is distance.
the input energy allways stays the same.
the output energy depends on the lenght of the system.

a quick determination.
how much power is required to move a single rubber duck a distance of 1000 miles if the rubber duck weights
100 lb?

528,000,000. ft-lbs

so if the ducks in the cannal move at 1 ft per second
and the ducks are 1 foot apart , then the system has
performed 528,000,000 ft-lbs of work on that particular duck.
and the system is performing a constant 528,000,000 ft-lbs per second , because it has delivered the duck the 1000 mile distance.
the duck traveled 5,280,000. ft and it took
5,280,000 seconds to get there.
so the system performed
1 lb x 5,280,000 ducks x 1 ft / 1 second.
5,280,000. ft-lbs/sec x 2 to move the ducks.

if I move the 100 lbs of water at each end a distance of say 10 ft each second to circulate the water
this is only 100 x 10 x 2 = 2000 lt-lbs/sec

try to explain that difference.

use any laws you choose or can make up to suit your
purpose.




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