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Moon and modern physics absurdities


Astronomy relates us about what is happening at thousands of year lights with the same certitude as when relates an experiment in laboratory.
It is high time to show to these astronomers that they are going into a wrong direction and they have no clue at least about what’s happening with closest celestial body – our satellite the Moon. Despite of facts it is a simple piece of matter, without atmosphere, without a significant magnetic field, without an internal structure, without performing relativistic acrobatics, Moon has something which turn over the entire modern science.
It is capable, with a certain delay, to transform itself into a microwave and radio partially polarised source when is illuminated by Sun. In a certain way it works like old lamps radios which need a period of time to heat up, until the signal is observed.
The Moon emission in microwave and radio domain is thousand up to millions times greater then blackbody predictions for its temperature.
In fact, after Sun, for an Earth observer, Moon is the second strong source of radio and microwave signal ever measured.
The explanation of this comportment will be made in next material when differences between electromagnetic waves and photons are analysed.
The link:
http://www.elkadot.com/ro/astronomie/luna_microunde.htm
A low cost experiment can be performed in laboratory to simulate lunar condition and show the real explanation for lunar radio emission, but I don’t think actual well bounded chairs people will be interested to perform such experiment and throw out their entire career …
But who cares!?

Best regards,
Sorin Cosofret

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I should know not to feed the trolls, but here I go.

Originally Posted By: sorincosofret
The Moon emission in microwave and radio domain is thousand up to millions times greater then blackbody predictions for its temperature.

Sorin, Do you have a source for this statement? I would like to make at least a quick check of your statement. One thing I can think of that might cause you to think this is if you are confusing the measurements. I checked and the following are the temperature facts I have found on the web.

Moon's Black Body Temperature = 270.7 deg K
Moon's max surface temperature = 396 deg K
Moon's min surface temperature = 40 deg K

Now obviously the sunny (hot) surface would emit quite a bit more radiation than the dark (cold) surface. So there might not be any inconsistency between the black body temperature and the radiated energy.

You say a low cost experiment can be performed to show the "real" explanation of lunar radiation. Will you pleas outline this experiment? And it would help your case a great deal if you would go ahead and perform the experiment and show the world that all the scientists are wrong.

Bill Gill


C is not the speed of light in a vacuum.
C is the universal speed limit.
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Originally Posted By: Bill
And it would help your case a great deal if you would go ahead and perform the experiment and show the world that all the scientists are wrong.


Surely, providing explicit proof ruins good trolling. smile


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In the mentioned link I have scanned a picture from a mainstream book with lunar emissive at different wavelength in radio and microwave (Kraus 1986) Figura2.
There is a calculation of blackbody emissive, and the maximum flux arriving on Earth, without taking into consideration a loss of signal.
As example, the maximum of signal arriving on Earth from illuminate surface of Moon have to be 0.71 Jy and after a certain time of rotation, from the dark side it have to be 0.17 Jy.
The measured value is 5x 10exp5 Jy.
The experiment will be described in the book and if I will have money I perform it. If some university or research center is interested, I suppose it will cost quite nothing becasue there are no new expensive materials or devices.

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Originally Posted By: sorincosofret
In the mentioned link I have scanned a picture from a mainstream book with lunar emissive at different wavelength in radio and microwave (Kraus 1986) Figura2.

Unfortunately I can't read the data in the link, and I don't have access to the book you scanned it from. Can you provide an available source. That would certainly be better than just having to take your word for it.

Bill Gill


C is not the speed of light in a vacuum.
C is the universal speed limit.
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Originally Posted By: Sorin
The experiment will be described in the book and if I will have money I perform it.


Go for it, Sorin. A theory that has been about for over a quarter of a century deserves to be tested. Whatever the outcome, it will probably militate against against any suspicions of trolling.


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So all you have to do is send a few Euro's to his Nigerian bank account for the test Bill S and he will do the test :-)

See the skeptic in me says if it's cheap and easy why wouldn't you do the experiment and claim the nobel prize!


I believe in "Evil, Bad, Ungodly fantasy science and maths", so I am undoubtedly wrong to you.
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Quote:
So all you have to do is send a few Euro's to his Nigerian bank account for the test Bill S


We don't have them in UK. I have only one Euro, and I use that in the trollies at Morrison's Supermarket. smile


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Bill,
You have to ask a professor of radio astronomy. I don’t have other reliable sources. Of course I consider internet a non reliable source. I can send you the name of the book and you can loan it from British library. The message is addressed to specialists, so if you are not able to perform yourself the calculation, the discussion is meaningless.
Orac
I will propose the experiment, maybe I will perform it. Performing or not performing an experiment is not a simple choice for me. I perform the experiments when I have doubts. With the new material related to electromagnetic waves and photons, I will set up the things so the experiment is redundant. Of course it can be performed only as a check…
Maybe actual physicists can afford few kEuro from the amount of billions spent on stupidities. For me, few kEuro is a considerable amount and I can perform other experiment where things are not clear and experimental part can help me to take a decision.


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