no way , if we can show it wont work then thats all it takes

otherwise we show it does work !!!

I found some information on a commercially sold product

that will help in our determination.

the generator complete

the generator and enginethe engine itself for specs.

the engine11 HP rated

5500 watt rated

6.6 gallon tank capacity

5.3 hrs. @ rated load (5500 watts)

Torque (ft./lbs.) 18.50 at 2,500 RPM

Max. RPM 3,600

Bore x Stroke (in.) 3.5 x 2.5

I suppose the rated HP , and rated 5500 watts utilize the maximum 3600 rpm.

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1 gallon = 3.785 liters

1 (cu in) = 0.016387064 liters

1 pound = 0.45359237 kilograms

6.6 gallons = 6.6 x 231 cu in = 1524.6 cu inch

1524.6 x 0.016387064 = 24.9837177744 liters

so 6.6 U.S. gallons = 24.9837177744 liters

gasoline weights from 5.8 to 6.5 lbs per gallon.

we can use 6 lbs per gallon.

we can use 2.721 kg per gallon

we have 6.6 gallons of gasoline x 6 pounds per gallon = 39.6 pounds per 6.6 gallons

we have 39.6 pounds of gasoline x 0.45359237 kilograms = 17.962 kilograms per 6.6 gallons

in 5.3 hours the gas engine uses 6.6 gallons

in 5.3 hours the gas engine uses 24.981 liters

so in 1 hour

6.6 gallons / 5.3 hours = 1.245 gallons

24.981 / 5.3 = 4.713 liters

in 1 hour the gas engine uses 1.245 gallons

in 1 hour the gas engine uses 4.713 liters

so in 1 minute

1.245 / 60 = 0.02075 gallons

4.713 / 60 = 0.07855 liters

in 1 minute the gas engine uses 0.02075 gallons

in 1 minute the gas engine uses 0.07855 liters

so in 1 second

0.02075 / 60 = 0.00034583 gallons

0.07855 / 60 = 0.00130916 liters

in 1 second the gas engine uses 0.00034583 gallons

in 1 second the gas engine uses 0.00130916 liters

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3600 rpm / 60 seconds = 60 revolutions per second.

a 4 stroke engine has 2 strokes per revolution

and only 1 of the 4 strokes is a intake stroke.

which equates to 15 intake strokes per second at 3600 rpm.

in 1 second the gas engine uses 0.00034583 gallons

in 1 second the gas engine uses 0.00130916 liters

which means that each intake stroke consumes

0.00034583 gallons / 15 = 0.0000230553 gallons per intake stroke

0.00130916 liters / 15 = 0.0000872773 liters per intake stroke

0.0000230553 gallons x 6 pounds per gallon = 0.0001383318 pounds

0.0001383318 pounds = 0.00006275 kg

gasoline has 44.4 Mj/kg energy content

Hydrogen has 142.0 Mj/kg energy content

44.4 Mj/kg x 0.00006275 kg = 0.0027861 Mj per stroke

44,000,000 j x 0.00006275 kg = 2786.1 j

since the power stroke comes from the energy content in the gasoline

the available energy from each power stroke is 0.0027861 Mj

or 2786.1 j

at 15 strokes per second the amount of energy avilable to the power stroke

is 2786.1 j x 15 = 41791.5 j or 41.7 kW

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wow now thats a lot of wasted energy wouldnt you say.

getting only 5.5 kW from a fuel that has 41.7 kW of energy in it!!!!!!!

what a waste , but anyway we now have several things to work with

we can just apply them to the HHO engine and see what the reults would be.

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so give me some time and I will try to see what I can come up with