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 #303 - 11/09/04 03:53 AM Conservation of Momentum: Inelastic Collisions Anonymous Unregistered My daughter is learning about mass, velocity and momentum... The teacher has only given partial instructions, and I'm not sure I have the correct answer. Formulas given: v=velocity, m=mass, p=momentumv=p/m, m=p/v, p=vmThis is the problem: Truck 1 (mass = 2500kg and velocity = 30m/s) hits Truck 2 (mass = 1500kg and velocity = 0m/s). Truck 1 and Truck 2 lock together. What is the final speed of both trucks?My guess at the solution is: T1: m=2500kg, v=30m/s, so p=2500kg*30m/s=75000kgm/sWhen it hits Truck 2, and the two trucks lock together, you combine the mass: (T1)2500kg + (T2)1500kg = (T1+T2)4000kgand divide the momentum (75000kgm/s) by the combined mass (4000kg), coming up with the combined velocity of 18.75m/s.Is this correct? Top
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 #304 - 11/09/04 12:39 PM Re: Conservation of Momentum: Inelastic Collisions Steerpike Junior Member Registered: 10/19/04 Posts: 3 Loc: UK Looks OK to me - keep Smiling! Top

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