750 kg*********************
solution no 1 traditional engine
F= m*V*V/ R
F- radial forces
R = 6 371 000 m ( Earth average )
F= 750 kg = 7500 N
V*V = 6 371 000 =====> V= 2525 m/s = 2,525 km/s
Orac I'm 100% sure that Engineers who made below airplane
understand problem very well
http://youtu.be/gWGLAAYdbbc*********************
Solution no 2 Marosz's , method
we have closed circut ( water )
inside pipe is propel srew
to eliminate reaction we can use
CW and CCW turbine system
************
we want to have F = 750 kg = 7500 N
**************
V1 = 10 [m/s] water's speed inside small pipe
R = 0,1 [m] radius
small pipe d = 0,001 [m]
big pipe D = 0,006 [m]
Small pipe water's mass
m1 = ?
( Pi*R * Pi*d1*d/4 = V1w pipe's capacity )
V1w = 0,00000024649000 [m3]
m1 = 998 [kg/m3] * V1w = 0,00024599702000 [kg]
Small pipe radial force
F1 m1 *V * V / R = 0,00024599702000 *10 *10 /0,1= 0,246 N
F1 = 0,246 N = 0,0246 [kg]
Radial Force inside big pipe = X * F1
X = ?
inside big pipe we have m2 = 36*m1 water ( pipe is 6x biger )
big pipe have the same long !!! R=0,1 [m]
Speed V2 =?
water's speed inside big pipe speed
V1 = 10 m/s V2 = 1/36 V1 (the same water' capacity escap from small pipe and go to big pipe )
F2 = 36m1 *(1/36)V1 *(1/36)V1 / R
F1 = m1 *V1*V1 / R
X= 1/36
F2 = 1/36 F1
m1 + m2
0,00024599702000 kg + 36 * 0,00024599702000 kg = 0,00910188974000 kg
F1 = 0,246 N = 0,0246 [kg]
Above engine can move up 2,5 x bigger Q than own
we can use Kirhoffe's rules to electric energy version
http://youtu.be/Aazwjy3n-fgORAC above classical equations
please back to Secoundary School "physics - Bernouli Rules , Kirchoffe rules " 
http://marosz-physics.blogspot.com/
