Originally Posted By: paul

you are talking about change in momentum which is nothing but the direction the mass is traveling.

I am talking about the forces applied to the pipe.

I'm also talking about the forces applied to the pipe. That's what I said. Please read more carefully.


The accelerator provides twice as much force the 2nd time round? OK that's fine. But it means the turnarounds also provide even more force:

+2 accelerator.
-3 1st turn.
+3 2nd turn.



Move the spaces in the list:


+1 accelerator.
-1 1st turn.

+1 2nd turn.
+2 accelerator.
-3 1st turn.

+3 2nd turn.
+3 accelerator.
-6 1st turn.

+6 2nd turn.
+4 accelerator.
-10 1st turn.


See how each group of 3 forces adds to zero? I've continued your pattern of the accelator's force increasing by 1 each cycle. But you can do that differently if you want, and they still add to zero.









Quote:

velocity = 5 meters per second = 5 m/s
velocity = 5 miles per hour = 5 miles/hour

speed = 5 meters per second = 5m/s
speed = 5 miles per hour = 5 miles / hour

they are both the distance traveled by the object and the time the object traveled.


No they're not the same. I'm really sure this is a big part of your consistent failure to understand anything I write. Until you find out the difference we may as well give up. I'm not going to the trouble of rewriting all my calculations using only speed and no velocity.