no way , if we can show it wont work then thats all it takes
otherwise we show it does work !!!
I found some information on a commercially sold product
that will help in our determination.
the generator complete
the generator and enginethe engine itself for specs.
the engine11 HP rated
5500 watt rated
6.6 gallon tank capacity
5.3 hrs. @ rated load (5500 watts)
Torque (ft./lbs.) 18.50 at 2,500 RPM
Max. RPM 3,600
Bore x Stroke (in.) 3.5 x 2.5
I suppose the rated HP , and rated 5500 watts utilize the maximum 3600 rpm.
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1 gallon = 3.785 liters
1 (cu in) = 0.016387064 liters
1 pound = 0.45359237 kilograms
6.6 gallons = 6.6 x 231 cu in = 1524.6 cu inch
1524.6 x 0.016387064 = 24.9837177744 liters
so 6.6 U.S. gallons = 24.9837177744 liters
gasoline weights from 5.8 to 6.5 lbs per gallon.
we can use 6 lbs per gallon.
we can use 2.721 kg per gallon
we have 6.6 gallons of gasoline x 6 pounds per gallon = 39.6 pounds per 6.6 gallons
we have 39.6 pounds of gasoline x 0.45359237 kilograms = 17.962 kilograms per 6.6 gallons
in 5.3 hours the gas engine uses 6.6 gallons
in 5.3 hours the gas engine uses 24.981 liters
so in 1 hour
6.6 gallons / 5.3 hours = 1.245 gallons
24.981 / 5.3 = 4.713 liters
in 1 hour the gas engine uses 1.245 gallons
in 1 hour the gas engine uses 4.713 liters
so in 1 minute
1.245 / 60 = 0.02075 gallons
4.713 / 60 = 0.07855 liters
in 1 minute the gas engine uses 0.02075 gallons
in 1 minute the gas engine uses 0.07855 liters
so in 1 second
0.02075 / 60 = 0.00034583 gallons
0.07855 / 60 = 0.00130916 liters
in 1 second the gas engine uses 0.00034583 gallons
in 1 second the gas engine uses 0.00130916 liters
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3600 rpm / 60 seconds = 60 revolutions per second.
a 4 stroke engine has 2 strokes per revolution
and only 1 of the 4 strokes is a intake stroke.
which equates to 15 intake strokes per second at 3600 rpm.
in 1 second the gas engine uses 0.00034583 gallons
in 1 second the gas engine uses 0.00130916 liters
which means that each intake stroke consumes
0.00034583 gallons / 15 = 0.0000230553 gallons per intake stroke
0.00130916 liters / 15 = 0.0000872773 liters per intake stroke
0.0000230553 gallons x 6 pounds per gallon = 0.0001383318 pounds
0.0001383318 pounds = 0.00006275 kg
gasoline has 44.4 Mj/kg energy content
Hydrogen has 142.0 Mj/kg energy content
44.4 Mj/kg x 0.00006275 kg = 0.0027861 Mj per stroke
44,000,000 j x 0.00006275 kg = 2786.1 j
since the power stroke comes from the energy content in the gasoline
the available energy from each power stroke is 0.0027861 Mj
or 2786.1 j
at 15 strokes per second the amount of energy avilable to the power stroke
is 2786.1 j x 15 = 41791.5 j or 41.7 kW
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wow now thats a lot of wasted energy wouldnt you say.
getting only 5.5 kW from a fuel that has 41.7 kW of energy in it!!!!!!!
what a waste , but anyway we now have several things to work with
we can just apply them to the HHO engine and see what the reults would be.
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so give me some time and I will try to see what I can come up with
