Kallog
we still have to push it into the pipe against the back-pressure of that column of air, which takes the same power as lifting the column of air itself, and in fact is what we are doing.
LOL
if the container at the bottom that is about to have the water in
it converted into HHO was at the top previously then it would have water and a small amount of air in it already and no HHO.
but its much simpler to use the pipe rather than the wheel , why you might ask?
because the pipe would cause less frictional loss than the wheel.
so I guess that removes your next straw.
using 2 pipes
(P1) to hold water, as it falls to the bottom.
and
(P2) to hold HHO as it rises to the top.
the water flows through a hydraulic motor at the bottom of (P1).
then enters the pipe (P2)that the HHO is in.
the water flows into the pipe (P2) via gravity.
water flows into pipe (P2) an into the HHO generator
located inside (P2)
pipe (P2) does not have an end on it at the bottom.
and the HHO is generated just above the bottom of the pipe
we have all seen that the HHO in all the videos floats upwards
in atmospheric pressure (1 atm) and there is no hardship placed
on the process due to atmospheric pressures or the buoyancy of HHO in air.
Im not sure that there wouldnt be some type of hardship placed
on it due to planetary alignment , or the coriolis effect
but I do know that HHO will float upwards in 1 atm pressure and that cannot be denied.
and I do know that water will flow down hill , that also cannot be denied.
now at the top of pipe (P2) the pipe is feeding HHO to
the power plant.
and the HHO at the top of (P2) will be slightly pressurized due to the buoyancy or density of HHO in air so it will
flow through to the power plant without undue strain or hardship.
dont believe me , try putting a glass held upside down over the top of a HHO generator , the HHO gasses will rise and push the air out of its way as it fills the upside down glass with HHO.
the power plant at the top will deposit the water from the power plant into the top of pipe (P1) which is open at the top to the atmospheric pressure.
now you could say that the water in pipe (P1) will evaporate
and that is true , some water will evaporate.
but if I add the amount of evaporated water at the bottom
of pipe (P2) then I dont need to lift it to the top , so no big deal as the company or home probably already has a 40 psi water
supply.
but you should also keep in mind that it rains these days
and a rain capture tank could be located at the top also !!
you should know by now that I dont believe in the energy conservation belief system that you believe in , as I know better.
I prefer to use the common sence method vs the theoretical
methods when determining if somethng will or will not work.
and just because you cant buy a FREE ENERGY system does not mean
that they cannot be built.
.
